Posted on 2008-05-15 01:12
yxc 阅读(6944)
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Struts2 、
MyEclipse
今天我用myeclipse做了一个关于struts2的小例子，和大家分享当然工程新建和服务器配置就不多说了！导入stuts2 的 jar包也不多说了！
首先配置web-inf下的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
右击src建立并配置struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<package name="struts2" extends="struts-default">
<action name="login" class="com.test.action.LoginAction">
<result name="input">login2.jsp</result>
<result>/result.jsp</result>
<result name="failer">/login2.jsp</result>
</action>
</package>
</struts>
并在src目录下建立包com.test.action,里面新建一个java类LoginAction.java
/*
*Coryright(c)2008 yxc & njust
*All rights reserved.
*/
package com.test.action;
import com.opensymphony.xwork2.ActionSupport;
public class LoginAction extends ActionSupport{ //此处继承的父类ActionSupport就是struts2的一个典型应用
private String username;
private String password;
public String getUsername()
{
return username;
}
public void setUsername(String username)
{
this.username = username;
}
public String getPassword()
{
return password;
}
public void setPassword(String password)
{
this.password = password;
}
public String execute() throws Exception
{
if("hello".equals(this.getUsername().trim())&&"word".equals(this.getPassword().trim()))
{
return "success";
}
else
{
this.addFieldError("username", "username or password error!!!!");
return "failer";
}
}
@Override
public void validate() { //验证
if(null==this.getUsername()|| "".equals(this.getUsername().trim()))
{
this.addFieldError("username", "username request");
}
if(null==this.getPassword()||"".equals(this.getPassword().trim()))
{
this.addFieldError("password", "password request");
}
}
}
在webroot下建立如下jsp文件，login2.jsp,result.jsp
login2.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="s" uri="/struts-tags" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<s:form action="login">
<s:textfield name="username" label="username"></s:textfield>
<s:password name="password" label="password"></s:password>
<s:submit name="submit"></s:submit>
</s:form>
</body>
</html>
result.jsp
<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'result.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
</head>
<body>
username:${requestScope.username}<br>
password:${requestScope.password}
</body>
</html>
这样就实现了简单的固定用户登陆，username:hello password:word
实现界面
