实现一个简单的struts2应用（实现登陆）

yxc — Wed, 14 May 2008 17:12:00 GMT

今天我用myeclipse做了一个关于struts2的小例子，和大家分享当然工程新建和服务器配置就不多说了！导入stuts2 的 jar包也不多说了！
首先配置web-inf下的web.xml

xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
    xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<filter>
<filter-name>struts2filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcherfilter-class>
filter>
<filter-mapping>
<filter-name>struts2filter-name>
<url-pattern>/*url-pattern>
filter-mapping>
web-app>

右击src建立并配置struts.xml

xml version="1.0" encoding="UTF-8" ?>
DOCTYPE struts PUBLIC
    "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
    "http://struts.apache.org/dtds/struts-2.0.dtd">

<struts>
   <package name="struts2"  extends="struts-default">
   <action name="login" class="com.test.action.LoginAction">
   <result name="input">login2.jspresult>
   <result>/result.jspresult>
   <result name="failer">/login2.jspresult>
   action>
   package>

struts>

并在src目录下建立包com.test.action,里面新建一个java类LoginAction.java

/*
*Coryright(c)2008 yxc & njust
*All rights reserved.
*/
package com.test.action;

import com.opensymphony.xwork2.ActionSupport;

public class LoginAction extends ActionSupport{  //此处继承的父类ActionSupport就是struts2的一个典型应用
    private String username;
    private String password;
    public String getUsername()
    {
        return username;
    }
    public void setUsername(String username)
    {
        this.username = username;
    }
    public String getPassword()
    {
        return password;
    }
    public void setPassword(String password)
    {
        this.password = password;
    }
    public String execute() throws Exception
    {
        if("hello".equals(this.getUsername().trim())&&"word".equals(this.getPassword().trim()))
        {
            return "success";
        }
        else
        {
            this.addFieldError("username", "username or password error!!!!");
            return "failer";
        }
    }
    @Override
    public void validate() {    //验证

        if(null==this.getUsername()|| "".equals(this.getUsername().trim()))
        {
            this.addFieldError("username", "username request");
        }
        if(null==this.getPassword()||"".equals(this.getPassword().trim()))
        {
            this.addFieldError("password", "password request");
        }
    }


}

在webroot下建立如下jsp文件，login2.jsp,result.jsp

login2.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="s"  uri="/struts-tags" %>
DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title heretitle>
head>
<body>
<s:form  action="login">
<s:textfield name="username" label="username">s:textfield>
<s:password name="password" label="password">s:password>
<s:submit name="submit">s:submit>
s:form>
body>
html>

result.jsp

<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
    <head>
    <base href="<%=basePath%>">
    <title>My JSP 'result.jsp' starting pagetitle>
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">

   head>
   <body>
    username:${requestScope.username}<br>
    password:${requestScope.password}
body>

html>

这样就实现了简单的固定用户登陆，username:hello password:word

实现界面

yxc 2008-05-15 01:12 发表评论

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实现一个简单的struts2应用（实现登陆）