Duran's technical life
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Suppose we start with a simple <one-to-many> association from Parent to Child.
 1<hibernate-mapping package="org.hibernate.auction.model">
 2 <class name="Parent" table="PARENT">
 3  <id name="id" column="PARENT_ID" type="long">
 4   <generator class="native"></generator>
 5  </id>
 6  <set name="children">
 7   <key column="MY_PARENT_ID" />
 8   <one-to-many class="org.hibernate.auction.model.Child" />
 9  </set>
10 </class>
11 <class name="Child" table="CHILD">
12  <id name="id" column="CHILD_ID" type="long">
13   <generator class="native"></generator>
14  </id>
15  <property name="name" column="NAME" type="string" />
16 </class>
17</hibernate-mapping>

If we were to execute the following code

 1Parent p = new Parent(new HashSet()); 
 2Child c1 = new Child(new String("c1"
));
 3

 4try 
{
 5    session =
 sessionFactory.openSession();            
 6    tx =
 session.beginTransaction();           
 7
    session.save(p);
 8    Long pid =
 p.getId();
 9
    tx.commit();
10
    session.close();
11
    
12    session =
 sessionFactory.openSession();
13    tx =
 session.beginTransaction();
14    Parent pp = (Parent) session.load(Parent.class
, pid); 
15
    pp.getChildren().add(c1);        
16
    session.save(c1);
17
    session.flush();
18
    tx.commit();
19

20}
 catch (HibernateException e) {
21}

Hibernate would issue two SQL statements:
- an INSERT to create the record for c
- an UPDATE to create the link from p to c

Hibernate: insert into PARENT values ( )
Hibernate: select parent0_.PARENT_ID as PARENT_ID0_ from PARENT parent0_ where parent0_.PARENT_ID=?
Hibernate: select children0_.MY_PARENT_ID as MY_PAREN3___, children0_.CHILD_ID as CHILD_ID__, children0_.CHILD_ID as CHILD_ID0_, children0_.NAME as NAME0_ from CHILD children0_ where children0_.MY_PARENT_ID=?

- Hibernate: insert into CHILD (NAME) values (?)
- Hibernate: update CHILD set MY_PARENT_ID=? where CHILD_ID=?

This is not only inefficient, but also violates any NOT NULL constraint on the
MY_PARENT_ID column.

**********1
The underlying cause is that the link (the foreign key parent_id) from p to c is not considered part of the state of the Child object and is therefore not created in the INSERT. So the solution is to make the link part of the Child mapping.
**********1

 <many-to-one name="my_parent"
  class
="org.hibernate.auction.model.Parent" column="MY_PARENT_ID"
  not-null
="true">
 
</many-to-one>

**********2
Now that the Child entity is managing the state of the link, we tell the collection not to update the link. We use the inverse attribute.
**********2

 <set name="children" inverse="true">
  
<key column="MY_PARENT_ID" />
  
<one-to-many class="org.hibernate.auction.model.Child" />
 
</set>

The following code would be used to add a new Child

1Parent pp = (Parent) session.load(Parent.class, pid); 
2
pp.getChildren().add(c1);
3c1.setMy_parent(pp); //the link is part of the Child object's state. @see***1 

4session.save(c1);

And now, only one SQL INSERT would be issued!
To tighten things up a bit, we could create an addChild() method of Parent.

1public void addChild(Child c) {
2  c.setParent(this
);
3
  children.add(c);
4}

Now, the code to add a Child looks like

1Parent p = (Parent) session.load(Parent.class, pid);
2Child c = new
 Child();
3p.addChild(c);  // 1.let both side of the association knows each other.

4session.save(c); // 2.save the non-verse side

=========================================================================================
CONCLUSION:
1.The non-inverse(inverse="false") side is responsible to save the in-memory representation (object) to the database .
--- you should save the child: session.save(c);
2.Changes made only to the inverse end of the association are not persisted.
--- you needn't update the parent: //session.update(p);

 1session = sessionFactory.openSession();
 2tx =
 session.beginTransaction();
 3Parent pp = (Parent) session.load(Parent.classnew Long(1
)); 
 4pp.getChildren().add(c1); //the parent(pp) now knowns about the relationship

 5c1.setMy_parent(pp); //the child(c1) now knows about the relationship
 6

 7//
 when cascade="save-update", update(p) will cause all p's
 8//
 referencing children become persistence(cascade 
 9//
 saveOrUpdate() operation to parent's all children).
10//
 So, it's same as you explicitly call session.save(c1).
11

12//
 when cascade="none"(default), update(p) will just cause
13//
 p become persistence.
14//
 And inverse="true", update(p) just persists p, but not 
15// persists the link between p and c1. @see ***2

16session.update(pp);  
17//session.save(c1);  

18session.flush();
19
tx.commit();
20


Hibernate: select parent0_.PARENT_ID as PARENT_ID0_ from PARENT parent0_ where parent0_.PARENT_ID=?
Hibernate: select children0_.MY_PARENT_ID as MY_PAREN3___, children0_.CHILD_ID as CHILD_ID__, children0_.CHILD_ID as CHILD_ID0_, children0_.NAME as NAME0_, children0_.MY_PARENT_ID as MY_PAREN3_0_ from CHILD children0_ where children0_.MY_PARENT_ID=?

 1session = sessionFactory.openSession();
 2tx =
 session.beginTransaction();
 3Parent pp = (Parent) session.load(Parent.classnew Long(1
)); 
 4
pp.getChildren().add(c1);
 5
c1.setMy_parent(pp);
 6//
session.update(pp);
 7

 8//
 when save(c1), because c1 holds a reference to its Parent
 9// (my_parent), so p become persistence too.

10session.save(c1);  //The relationship will be saved. @see ***1
11session.flush();
12
tx.commit();
13


Hibernate: select parent0_.PARENT_ID as PARENT_ID0_ from PARENT parent0_ where parent0_.PARENT_ID=?
Hibernate: select children0_.MY_PARENT_ID as MY_PAREN3___, children0_.CHILD_ID as CHILD_ID__, children0_.CHILD_ID as CHILD_ID0_, children0_.NAME as NAME0_, children0_.MY_PARENT_ID as MY_PAREN3_0_ from CHILD children0_ where children0_.MY_PARENT_ID=?
Hibernate: insert into CHILD (NAME, MY_PARENT_ID) values (?, ?)


 

posted on 2005-05-19 09:28 Duran's technical life 阅读(564) 评论(0)  编辑  收藏 所属分类: 技术积累

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