Quartz优先级的使用

建三个Job类:

import org.quartz.Job;

import org.quartz.JobExecutionContext;

import org.quartz.JobExecutionException;

public class JobTest1 implements Job

{

public void execute(JobExecutionContext jobexecutioncontext)

throws JobExecutionException

{

System.out.println("JobTest1");

}

import org.quartz.Job;

import org.quartz.JobExecutionContext;

import org.quartz.JobExecutionException;

public class JobTest2 implements Job

{

public void execute(JobExecutionContext jobexecutioncontext)

throws JobExecutionException

{

System.out.println("JobTest2");

}

import org.quartz.Job;

import org.quartz.JobExecutionContext;

import org.quartz.JobExecutionException;

public class JobTest3 implements Job

{

public void execute(JobExecutionContext jobexecutioncontext)

throws JobExecutionException

{

System.out.println("JobTest3");

}

比较简单,上面三个类就不多说了.
测试类:

import java.util.Date;

import org.quartz.JobDetail;

import org.quartz.Scheduler;

import org.quartz.SchedulerFactory;

import org.quartz.SimpleTrigger;

import org.quartz.Trigger;

import org.quartz.impl.StdSchedulerFactory;

public class PriorityTest

{

public static void main(String[] args) throws Exception

{

SchedulerFactory sf = new StdSchedulerFactory();

Scheduler scheduler = sf.getScheduler();

JobDetail job1 = new JobDetail();

job1.setName("jobDetail1");

job1.setGroup("a");

job1.setJobClass(JobTest1.class);

JobDetail job2 = new JobDetail();

job2.setName("jobDetail2");

job2.setGroup("b");

job2.setJobClass(JobTest2.class);

JobDetail job3 = new JobDetail();

job3.setName("jobDetail3");

job3.setGroup("c");

job3.setJobClass(JobTest3.class);

Trigger trigger1 = new SimpleTrigger();

trigger1.setName("trigger1");

trigger1.setStartTime(new Date());

//优先级默认是5

trigger1.setPriority(Trigger.DEFAULT_PRIORITY);

Trigger trigger2 = new SimpleTrigger();

trigger2.setName("trigger2");

trigger2.setStartTime(new Date());

trigger2.setPriority(100);

Trigger trigger3 = new SimpleTrigger();

trigger3.setName("trigger3");

trigger3.setStartTime(new Date());

trigger3.setPriority(15);

scheduler.scheduleJob(job1, trigger1);

scheduler.scheduleJob(job2, trigger2);

scheduler.scheduleJob(job3, trigger3);

scheduler.start();

}

输出:

JobTest2

JobTest3

JobTest1

由此我们可以看出优先级决定于整形数值的大小.
数值越大优先级越高.

posted on 2008-05-08 16:36 々上善若水々阅读(63) 评论(0) 编辑收藏所属分类: opensource

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