Posted on 2008-08-22 17:41
Kevin Meng 阅读(2412)
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（1）在eclipse中配置好struts2
（2）把struts2-spring-plugin-2.0.11.2.jar包复制到WEB-INF\lib目录
（3）在web.xml中配置spring
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
记住，如果您之前用过spring，请把spring配置去掉。
<servlet>
<servlet-name>context</servlet-name>
<servlet-class>
org.springframework.web.context.ContextLoaderServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
（4）修改applicationContext.xml
<beans
default-autowire="byName" xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd">
（5）在struts.xml加入
<constant name="struts.objectFactory" value="spring" />
（6）在spring的配置文件applicationContext.xml中定义action
<bean id="
SearchBusLineAction"
class="com.bus.struts2.action.SearchBusLineAction" abstract="false"
lazy-init="default" autowire="default" dependency-check="default">
<property name="busService">
<ref bean="BusServiceImpl" />
</property>
</bean>
（7）在struts.xml中定义action
<!-- 注意这里class="
SearchBusLineAction"而不是com.bus.struts2.action.SearchBusLineAction是因为这个已经在spring的applicationContext.xml中定义 -->
<action name="searchBusLine" class="SearchBusLineAction">
<result name="success" type="freemarker">/index.jsp</result>
</action>