[精华] md5算法的java源代码!
http://www.chinaunix.net 作者:ii 发表于：2003-08-19 02:57:15
public class MD5
{
/*
* A Java implementation of the RSA Data Security, Inc. MD5
Message
* Digest Algorithm, as defined in RFC 1321.
* Based on the JavaScript implementation of Paul Johnston
* Copyright (C) Paul Johnston 1999 - 2000.
* See http://pajhome.org.uk/site/legal.html for
details.
* Java Version by Thomas Weber (Orange Interactive GmbH)
*/
/*
* Convert a 32-bit number to a hex string with ls-byte
first
*/
String hex_chr = "0123456789abcdef";
private String rhex(int num)
{
String str = "";
for(int j = 0; j <= 3; j++)
str = str + hex_chr.charAt((num >;>; (j * 8 + 4)) &
0x0F) + hex_chr.charAt((num >;>; (j * 8)) & 0x0F);
return str;
}
/*
* Convert a string to a sequence of 16-word blocks, stored
as an array.
* Append padding bits and the length, as described in the
MD5 standard.
*/
private int[] str2blks_MD5(String str)
{
int nblk = ((str.length() + 8) >;>; 6) + 1;
int[] blks = new int[nblk * 16];
int i = 0;
for(i = 0; i < nblk * 16; i++) {
blks = 0;
}
for(i = 0; i < str.length(); i++) {
blks[i >;>; 2] |= str.charAt(i) << ((i % 4) * 8);
}
blks[i >;>; 2] |= 0x80 << ((i % 4) * 8);
blks[nblk * 16 - 2] = str.length()*8;
return blks;
}
/*
* Add integers, wrapping at 2^32
*/
private int add(int x, int y)
{
return ((x&0x7FFFFFFF) + (y&0x7FFFFFFF)) ^
(x&0x80000000) ^ (y&0x80000000);
}
/*
* Bitwise rotate a 32-bit number to the left
*/
private int rol(int num, int cnt)
{
return (num << cnt) | (num >;>;>; (32 - cnt));
}
/*
* These functions implement the basic operation for each
round of the
* algorithm.
*/
private int cmn(int q, int a, int b, int x, int s, int t)
{
return add(rol(add(add(a, q), add(x, t)), s), b);
}
private int ff(int a, int b, int c, int d, int x, int s, int
t)
{
return cmn((b & c) | ((~b) & d), a, b, x, s, t);
}
private int gg(int a, int b, int c, int d, int x, int s, int
t)
{
return cmn((b & d) | (c & (~d)), a, b, x, s, t);
}
private int hh(int a, int b, int c, int d, int x, int s, int
t)
{
return cmn(b ^ c ^ d, a, b, x, s, t);
}
private int ii(int a, int b, int c, int d, int x, int s, int
t)
{
return cmn(c ^ (b | (~d)), a, b, x, s, t);
}
/*
* Take a string and return the hex representation of its
MD5.
*/
public String calcMD5(String str)
{
int[] x = str2blks_MD5(str);
int a = 0x67452301;
int b = 0xEFCDAB89;
int c = 0x98BADCFE;
int d = 0x10325476;
for(int i = 0; i < x.length; i += 16)
{
int olda = a;
int oldb = b;
int oldc = c;
int oldd = d;
a = ff(a, b, c, d, x[i+ 0], 7 , 0xD76AA478);
d = ff(d, a, b, c, x[i+ 1], 12, 0xE8C7B756);
c = ff(c, d, a, b, x[i+ 2], 17, 0x242070DB);
b = ff(b, c, d, a, x[i+ 3], 22, 0xC1BDCEEE);
a = ff(a, b, c, d, x[i+ 4], 7 , 0xF57C0FAF);
d = ff(d, a, b, c, x[i+ 5], 12, 0x4787C62A);
c = ff(c, d, a, b, x[i+ 6], 17, 0xA8304613);
b = ff(b, c, d, a, x[i+ 7], 22, 0xFD469501);
a = ff(a, b, c, d, x[i+ 8], 7 , 0x698098D8);
d = ff(d, a, b, c, x[i+ 9], 12, 0x8B44F7AF);
c = ff(c, d, a, b, x[i+10], 17, 0xFFFF5BB1);
b = ff(b, c, d, a, x[i+11], 22, 0x895CD7BE);
a = ff(a, b, c, d, x[i+12], 7 , 0x6B901122);
d = ff(d, a, b, c, x[i+13], 12, 0xFD987193);
c = ff(c, d, a, b, x[i+14], 17, 0xA679438E);
b = ff(b, c, d, a, x[i+15], 22, 0x49B40821);
a = gg(a, b, c, d, x[i+ 1], 5 , 0xF61E2562);
d = gg(d, a, b, c, x[i+ 6], 9 , 0xC040B340);
c = gg(c, d, a, b, x[i+11], 14, 0x265E5A51);
b = gg(b, c, d, a, x[i+ 0], 20, 0xE9B6C7AA);
a = gg(a, b, c, d, x[i+ 5], 5 , 0xD62F105D);
d = gg(d, a, b, c, x[i+10], 9 , 0x02441453);
c = gg(c, d, a, b, x[i+15], 14, 0xD8A1E681);
b = gg(b, c, d, a, x[i+ 4], 20, 0xE7D3FBC8);
a = gg(a, b, c, d, x[i+ 9], 5 , 0x21E1CDE6);
d = gg(d, a, b, c, x[i+14], 9 , 0xC33707D6);
c = gg(c, d, a, b, x[i+ 3], 14, 0xF4D50D87);
b = gg(b, c, d, a, x[i+ 8], 20, 0x455A14ED);
a = gg(a, b, c, d, x[i+13], 5 , 0xA9E3E905);
d = gg(d, a, b, c, x[i+ 2], 9 , 0xFCEFA3F8);
c = gg(c, d, a, b, x[i+ 7], 14, 0x676F02D9);
b = gg(b, c, d, a, x[i+12], 20, 0x8D2A4C8A);
a = hh(a, b, c, d, x[i+ 5], 4 , 0xFFFA3942);
d = hh(d, a, b, c, x[i+ 8], 11, 0x8771F681);
c = hh(c, d, a, b, x[i+11], 16, 0x6D9D6122);
b = hh(b, c, d, a, x[i+14], 23, 0xFDE5380C);
a = hh(a, b, c, d, x[i+ 1], 4 , 0xA4BEEA44);
d = hh(d, a, b, c, x[i+ 4], 11, 0x4BDECFA9);
c = hh(c, d, a, b, x[i+ 7], 16, 0xF6BB4B60);
b = hh(b, c, d, a, x[i+10], 23, 0xBEBFBC70);
a = hh(a, b, c, d, x[i+13], 4 , 0x289B7EC6);
d = hh(d, a, b, c, x[i+ 0], 11, 0xEAA127FA);
c = hh(c, d, a, b, x[i+ 3], 16, 0xD4EF3085);
b = hh(b, c, d, a, x[i+ 6], 23, 0x04881D05);
a = hh(a, b, c, d, x[i+ 9], 4 , 0xD9D4D039);
d = hh(d, a, b, c, x[i+12], 11, 0xE6DB99E5);
c = hh(c, d, a, b, x[i+15], 16, 0x1FA27CF8);
b = hh(b, c, d, a, x[i+ 2], 23, 0xC4AC5665);
a = ii(a, b, c, d, x[i+ 0], 6 , 0xF4292244);
d = ii(d, a, b, c, x[i+ 7], 10, 0x432AFF97);
c = ii(c, d, a, b, x[i+14], 15, 0xAB9423A7);
b = ii(b, c, d, a, x[i+ 5], 21, 0xFC93A039);
a = ii(a, b, c, d, x[i+12], 6 , 0x655B59C3);
d = ii(d, a, b, c, x[i+ 3], 10, 0x8F0CCC92);
c = ii(c, d, a, b, x[i+10], 15, 0xFFEFF47D);
b = ii(b, c, d, a, x[i+ 1], 21, 0x85845DD1);
a = ii(a, b, c, d, x[i+ 8], 6 , 0x6FA87E4F);
d = ii(d, a, b, c, x[i+15], 10, 0xFE2CE6E0);
c = ii(c, d, a, b, x[i+ 6], 15, 0xA3014314);
b = ii(b, c, d, a, x[i+13], 21, 0x4E0811A1);
a = ii(a, b, c, d, x[i+ 4], 6 , 0xF7537E82);
d = ii(d, a, b, c, x[i+11], 10, 0xBD3AF235);
c = ii(c, d, a, b, x[i+ 2], 15, 0x2AD7D2BB);
b = ii(b, c, d, a, x[i+ 9], 21, 0xEB86D391);
a = add(a, olda);
b = add(b, oldb);
c = add(c, oldc);
d = add(d, oldd);
}
return rhex(a) + rhex(b) + rhex(c) + rhex(d);
}
}
ii 回复于：2003-01-28 13:51:46
另: 一中国人写的md5 的javabean:
/************************************************
MD5 算法的Java Bean
@author:Topcat Tuppin
Last Modified:10,Mar,2001
*************************************************/
//package beartool;
import java.lang.reflect.*;
/*************************************************
md5 类实现了RSA Data Security, Inc.在提交给IETF
的RFC1321中的MD5 message-digest 算法。
*************************************************/
public class MD5 {
/* 下面这些S11-S44实际上是一个4*4的矩阵，在原始的C实现中是用#define 实现的，
这里把它们实现成为static final是表示了只读，切能在同一个进程空间内的多个
Instance间共享*/
static final int S11 = 7;
static final int S12 = 12;
static final int S13 = 17;
static final int S14 = 22;
static final int S21 = 5;
static final int S22 = 9;
static final int S23 = 14;
static final int S24 = 20;
static final int S31 = 4;
static final int S32 = 11;
static final int S33 = 16;
static final int S34 = 23;
static final int S41 = 6;
static final int S42 = 10;
static final int S43 = 15;
static final int S44 = 21;
static final byte[] PADDING = { -128, 0, 0, 0, 0, 0,
0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0 };
/* 下面的三个成员是MD5计算过程中用到的3个核心数据，在原始的C实现中
被定义到MD5_CTX结构中
*/
private long[] state = new long[4]; // state (ABCD)
private long[] count = new long[2]; // number of
bits, modulo 2^64 (lsb first)
private byte[] buffer = new byte[64]; // input buffer
/* digestHexStr是MD5的唯一一个公共成员，是最新一次计算结果的
16进制ASCII表示.
*/
public String digestHexStr;
/* digest,是最新一次计算结果的2进制内部表示，表示128bit的MD5值.
*/
private byte[] digest = new byte[16];
/*
getMD5ofStr是类MD5最主要的公共方法，入口参数是你想要进行MD5变换的字符串
返回的是变换完的结果，这个结果是从公共成员digestHexStr取得的．
*/
public String getMD5ofStr(String inbuf) {
md5Init();
md5Update(inbuf.getBytes(), inbuf.length());
md5Final();
digestHexStr = "";
for (int i = 0; i < 16; i++) {
digestHexStr += byteHEX(digest);
}
return digestHexStr;
}
// 这是MD5这个类的标准构造函数，JavaBean要求有一个public的并且没有参数的构造函数
public MD5() {
md5Init();
return;
}
/* md5Init是一个初始化函数，初始化核心变量，装入标准的幻数 */
private void md5Init() {
count[0] = 0L;
count[1] = 0L;
///* Load magic initialization constants.
state[0] = 0x67452301L;
state[1] = 0xefcdab89L;
state[2] = 0x98badcfeL;
state[3] = 0x10325476L;
return;
}
/* F, G, H ,I 是4个基本的MD5函数，在原始的MD5的C实现中，由于它们是
简单的位运算，可能出于效率的考虑把它们实现成了宏，在java中，我们把它们
实现成了private方法，名字保持了原来C中的。 */
private long F(long x, long y, long z) {
return (x & y) | ((~x) & z);
}
private long G(long x, long y, long z) {
return (x & z) | (y & (~z));
}
private long H(long x, long y, long z) {
return x ^ y ^ z;
}
private long I(long x, long y, long z) {
return y ^ (x | (~z));
}
/*
FF,GG,HH和II将调用F,G,H,I进行近一步变换
FF, GG, HH, and II transformations for rounds 1, 2,
3, and 4.
Rotation is separate from addition to prevent
recomputation.
*/
private long FF(long a, long b, long c, long d, long
x, long s,
long ac) {
a += F (b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >;>;>; (32 -
s));
a += b;
return a;
}
private long GG(long a, long b, long c, long d, long
x, long s,
long ac) {
a += G (b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >;>;>; (32 -
s));
a += b;
return a;
}
private long HH(long a, long b, long c, long d, long
x, long s,
long ac) {
a += H (b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >;>;>; (32 -
s));
a += b;
return a;
}
private long II(long a, long b, long c, long d, long
x, long s,
long ac) {
a += I (b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >;>;>; (32 -
s));
a += b;
return a;
}
/*
md5Update是MD5的主计算过程，inbuf是要变换的字节串，inputlen是长度，这个
函数由getMD5ofStr调用，调用之前需要调用md5init，因此把它设计成private的
*/
private void md5Update(byte[] inbuf, int inputLen) {
int i, index, partLen;
byte[] block = new byte[64];
index = (int)(count[0] >;>;>; 3) & 0x3F;
// /* Update number of bits */
if ((count[0] += (inputLen << 3)) < (inputLen
<< 3))
count[1]++;
count[1] += (inputLen >;>;>; 29);
partLen = 64 - index;
// Transform as many times as possible.
if (inputLen >;= partLen) {
md5Memcpy(buffer, inbuf, index, 0,
partLen);
md5Transform(buffer);
for (i = partLen; i + 63 < inputLen; i
+= 64) {
md5Memcpy(block, inbuf, 0, i,
64);
md5Transform (block);
}
index = 0;
} else
i = 0;
///* Buffer remaining input */
md5Memcpy(buffer, inbuf, index, i, inputLen -
i);
}
/*
md5Final整理和填写输出结果
*/
private void md5Final () {
byte[] bits = new byte[8];
int index, padLen;
///* Save number of bits */
Encode (bits, count, 8);
///* Pad out to 56 mod 64.
index = (int)(count[0] >;>;>; 3) & 0x3f;
padLen = (index < 56) ? (56 - index) : (120 -
index);
md5Update (PADDING, padLen);
///* Append length (before padding) */
md5Update(bits, 8);
///* Store state in digest */
Encode (digest, state, 16);
}
/* md5Memcpy是一个内部使用的byte数组的块拷贝函数，从input的inpos开始把len长度的
字节拷贝到output的outpos位置开始
*/
private void md5Memcpy (byte[] output, byte[] input,
int outpos, int inpos, int len)
{
int i;
for (i = 0; i < len; i++)
output[outpos + i] = input[inpos + i];
}
/*
md5Transform是MD5核心变换程序，有md5Update调用，block是分块的原始字节
*/
private void md5Transform (byte block[]) {
long a = state[0], b = state[1], c = state[2],
d = state[3];
long[] x = new long[16];
Decode (x, block, 64);
/* Round 1 */
a = FF (a, b, c, d, x[0], S11, 0xd76aa478L);
/* 1 */
d = FF (d, a, b, c, x[1], S12, 0xe8c7b756L);
/* 2 */
c = FF (c, d, a, b, x[2], S13, 0x242070dbL);
/* 3 */
b = FF (b, c, d, a, x[3], S14, 0xc1bdceeeL);
/* 4 */
a = FF (a, b, c, d, x[4], S11, 0xf57c0fafL);
/* 5 */
d = FF (d, a, b, c, x[5], S12, 0x4787c62aL);
/* 6 */
c = FF (c, d, a, b, x[6], S13, 0xa8304613L);
/* 7 */
b = FF (b, c, d, a, x[7], S14, 0xfd469501L);
/* 8 */
a = FF (a, b, c, d, x[8], S11, 0x698098d8L);
/* 9 */
d = FF (d, a, b, c, x[9], S12, 0x8b44f7afL);
/* 10 */
c = FF (c, d, a, b, x[10], S13, 0xffff5bb1L);
/* 11 */
b = FF (b, c, d, a, x[11], S14, 0x895cd7beL);
/* 12 */
a = FF (a, b, c, d, x[12], S11, 0x6b901122L);
/* 13 */
d = FF (d, a, b, c, x[13], S12, 0xfd987193L);
/* 14 */
c = FF (c, d, a, b, x[14], S13, 0xa679438eL);
/* 15 */
b = FF (b, c, d, a, x[15], S14, 0x49b40821L);
/* 16 */
/* Round 2 */
a = GG (a, b, c, d, x[1], S21, 0xf61e2562L);
/* 17 */
d = GG (d, a, b, c, x[6], S22, 0xc040b340L);
/* 18 */
c = GG (c, d, a, b, x[11], S23, 0x265e5a51L);
/* 19 */
b = GG (b, c, d, a, x[0], S24, 0xe9b6c7aaL);
/* 20 */
a = GG (a, b, c, d, x[5], S21, 0xd62f105dL);
/* 21 */
d = GG (d, a, b, c, x[10], S22, 0x2441453L);
/* 22 */
c = GG (c, d, a, b, x[15], S23, 0xd8a1e681L);
/* 23 */
b = GG (b, c, d, a, x[4], S24, 0xe7d3fbc8L);
/* 24 */
a = GG (a, b, c, d, x[9], S21, 0x21e1cde6L);
/* 25 */
d = GG (d, a, b, c, x[14], S22, 0xc33707d6L);
/* 26 */
c = GG (c, d, a, b, x[3], S23, 0xf4d50d87L);
/* 27 */
b = GG (b, c, d, a, x[8], S24, 0x455a14edL);
/* 28 */
a = GG (a, b, c, d, x[13], S21, 0xa9e3e905L);
/* 29 */
d = GG (d, a, b, c, x[2], S22, 0xfcefa3f8L);
/* 30 */
c = GG (c, d, a, b, x[7], S23, 0x676f02d9L);
/* 31 */
b = GG (b, c, d, a, x[12], S24, 0x8d2a4c8aL);
/* 32 */
/* Round 3 */
a = HH (a, b, c, d, x[5], S31, 0xfffa3942L);
/* 33 */
d = HH (d, a, b, c, x[8], S32, 0x8771f681L);
/* 34 */
c = HH (c, d, a, b, x[11], S33, 0x6d9d6122L);
/* 35 */
b = HH (b, c, d, a, x[14], S34, 0xfde5380cL);
/* 36 */
a = HH (a, b, c, d, x[1], S31, 0xa4beea44L);
/* 37 */
d = HH (d, a, b, c, x[4], S32, 0x4bdecfa9L);
/* 38 */
c = HH (c, d, a, b, x[7], S33, 0xf6bb4b60L);
/* 39 */
b = HH (b, c, d, a, x[10], S34, 0xbebfbc70L);
/* 40 */
a = HH (a, b, c, d, x[13], S31, 0x289b7ec6L);
/* 41 */
d = HH (d, a, b, c, x[0], S32, 0xeaa127faL);
/* 42 */
c = HH (c, d, a, b, x[3], S33, 0xd4ef3085L);
/* 43 */
b = HH (b, c, d, a, x[6], S34, 0x4881d05L); /*
44 */
a = HH (a, b, c, d, x[9], S31, 0xd9d4d039L);
/* 45 */
d = HH (d, a, b, c, x[12], S32, 0xe6db99e5L);
/* 46 */
c = HH (c, d, a, b, x[15], S33, 0x1fa27cf8L);
/* 47 */
b = HH (b, c, d, a, x[2], S34, 0xc4ac5665L);
/* 48 */
/* Round 4 */
a = II (a, b, c, d, x[0], S41, 0xf4292244L);
/* 49 */
d = II (d, a, b, c, x[7], S42, 0x432aff97L);
/* 50 */
c = II (c, d, a, b, x[14], S43, 0xab9423a7L);
/* 51 */
b = II (b, c, d, a, x[5], S44, 0xfc93a039L);
/* 52 */
a = II (a, b, c, d, x[12], S41, 0x655b59c3L);
/* 53 */
d = II (d, a, b, c, x[3], S42, 0x8f0ccc92L);
/* 54 */
c = II (c, d, a, b, x[10], S43, 0xffeff47dL);
/* 55 */
b = II (b, c, d, a, x[1], S44, 0x85845dd1L);
/* 56 */
a = II (a, b, c, d, x[8], S41, 0x6fa87e4fL);
/* 57 */
d = II (d, a, b, c, x[15], S42, 0xfe2ce6e0L);
/* 58 */
c = II (c, d, a, b, x[6], S43, 0xa3014314L);
/* 59 */
b = II (b, c, d, a, x[13], S44, 0x4e0811a1L);
/* 60 */
a = II (a, b, c, d, x[4], S41, 0xf7537e82L);
/* 61 */
d = II (d, a, b, c, x[11], S42, 0xbd3af235L);
/* 62 */
c = II (c, d, a, b, x[2], S43, 0x2ad7d2bbL);
/* 63 */
b = II (b, c, d, a, x[9], S44, 0xeb86d391L);
/* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
}
/*Encode把long数组按顺序拆成byte数组，因为java的long类型是64bit的，
只拆低32bit，以适应原始C实现的用途
*/
private void Encode (byte[] output, long[] input, int
len) {
int i, j;
for (i = 0, j = 0; j < len; i++, j += 4) {
output[j] = (byte)(input & 0xffL);
output[j + 1] = (byte)((input >;>;>;
8) & 0xffL);
output[j + 2] = (byte)((input >;>;>;
16) & 0xffL);
output[j + 3] = (byte)((input >;>;>;
24) & 0xffL);
}
}
/*Decode把byte数组按顺序合成成long数组，因为java的long类型是64bit的，
只合成低32bit，高32bit清零，以适应原始C实现的用途
*/
private void Decode (long[] output, byte[] input, int
len) {
int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
output = b2iu(input[j]) |
(b2iu(input[j + 1]) << 8) |
(b2iu(input[j + 2]) << 16) |
(b2iu(input[j + 3]) << 24);
return;
}
/*
b2iu是我写的一个把byte按照不考虑正负号的原则的＂升位＂程序，因为java没有unsigned运算
*/
public static long b2iu(byte b) {
return b < 0 ? b & 0x7F + 128 : b;
}
/*byteHEX()，用来把一个byte类型的数转换成十六进制的ASCII表示，
因为java中的byte的toString无法实现这一点，我们又没有C语言中的
sprintf(outbuf,"%02X",ib)
*/
public static String byteHEX(byte ib) {
char[] Digit = {
'0','1','2','3','4','5','6','7','8','9',
'A','B','C','D','E','F' };
char [] ob = new char[2];
ob[0] = Digit[(ib >;>;>; 4) & 0X0F];
ob[1] = Digit[ib & 0X0F];
String s = new String(ob);
return s;
}
public static void main(String args[]) {
MD5 m = new MD5();
if (Array.getLength(args) == 0) {
//如果没有参数，执行标准的Test Suite
System.out.println("MD5 Test suite:");
System.out.println("MD5(\"\"):"+m.getMD5ofStr(""));
System.out.println("MD5(\"a\"):"+m.getMD5ofStr("a"));
System.out.println("MD5(\"abc\"):"+m.getMD5ofStr("abc"));
System.out.println("MD5(\"message
digest\"):"+m.getMD5ofStr("message digest"));
System.out.println("MD5(\"abcdefghijklmnopqrstuvwxyz\"):"+
m.getMD5ofStr("abcdefghijklmnopqrstuvwxyz"));
System.out.println("MD5(\"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789\"):"+
m.getMD5ofStr("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"));
}
else
System.out.println("MD5(" + args[0] +
")=" + m.getMD5ofStr(args[0]));
}
}
ii 回复于：2003-02-09 09:40:22
再次改人家的程序，来简化处理.
// 程序名为MMM.java
package md5;
import java.security.*;
public class MMM {
public String calcMD5(String str) {
try {
MessageDigest alga=MessageDigest.getInstance("MD5");
// MessageDigest alga=MessageDigest.getInstance("SHA-1");
alga.update(str.getBytes());
byte[] digesta=alga.digest();
return byte2hex(digesta);
}
catch (NoSuchAlgorithmException ex)
{ System.out.println("大哥，出错了！！"); }
return "NULL";
}
public String byte2hex(byte[] b) { //二行制转字符串
String hs="";
String stmp="";
for (int n=0;n<b.length;n++) {
stmp=(Integer.toHexString(b[n] & 0XFF));
if (stmp.length()==1) hs=hs+"0"+stmp;
else hs=hs+stmp;
if (n<b.length-1) hs=hs+"";
}
// return hs.toUpperCase();
return hs;
}
}
原文链接：http://bbs.chinaunix.net/viewthread.php?tid=8972
转载请注明作者名及原文出处
posted on 2008-02-13 11:16
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