2009年3月21日随笔档案 - javait

2009年3月21日

SRM 147 CCipher

import java.lang.*;
2

import java.util.*;
3

public class CCipher {
5

public String decode(String cipherText, int shift) {
6

StringBuffer ans = new StringBuffer();
8

for (int i = 0; i < cipherText.length(); ++i) {
9

char ch = cipherText.charAt(i);
10

if (ch - 'A' - shift < 0) {
11

ch += 26 - shift;
12

} else {
13

ch -= shift;
14

}
15

ans.append(ch);
16

}
17

return ans.toString();
18

}
20

}

posted @ 2009-04-05 20:09 edwing 阅读(106) | 评论 (0) | 编辑收藏

SRM 149 FormatAmt

import java.util.*;
2

import java.lang.*;
3

public class FormatAmt {
5

public String amount(int dollars, int cents) {
7

String ans = "";
9

String dollarsStr = String.valueOf(dollars);
10

int n = dollarsStr.length();
11

int begin = (3 - (n % 3)) % 3;
12

for (int i = 0, j = begin; i < n; ++i, j = (++j) % 3) {
13

if (i != 0 && j == 0) {
14

ans += ",";
15

}
16

ans += dollarsStr.charAt(i);
17

}
18

ans = "$" + ans + ".";
19

if (cents < 10) {
20

ans += "0" + cents;
21

} else {
22

ans += cents;
23

}
24

return ans;
25

}
27

}

posted @ 2009-04-05 20:07 edwing 阅读(111) | 评论 (0) | 编辑收藏

SRM 148 DivisorDigits

import java.util.*;
2

import java.lang.*;
3

public class DivisorDigits {
5

public int howMany(int number) {
6

int ans = 0;
8

int n = number;
9

while (n != 0) {
10

int n1 = n % 10;
11

if (n1 != 0 && number % n1 == 0) {
12

++ans;
13

}
14

n /= 10;
15

}
16

return ans;
17

}
19

}

posted @ 2009-03-21 10:27 edwing 阅读(109) | 评论 (0) | 编辑收藏

SRM 145 ImageDithering

import java.util.*;
2

public class ImageDithering {
4

public int count(String dithered, String[] screen) {
5

int ans = 0;
6

for (int i = 0; i < screen.length; ++i) {
7

for (int j = 0; j < screen[0].length(); ++j) {
8

char ch = screen[i].charAt(j);
9

if (dithered.indexOf(ch) != -1) {
10

++ans;
11

}
12

}
13

}
14

return ans;
15

}
16

}

posted @ 2009-03-21 10:21 edwing 阅读(84) | 评论 (0) | 编辑收藏

SRM 144 Time

public class Time {
2

public String whatTime(int seconds) {
3

int h = seconds / 3600;
4

int m = seconds / 60 % 60;
5

int s = seconds % 60;
6

return (h + ":" + m + ":" + s);
7

}
8

}

posted @ 2009-03-21 10:17 edwing 阅读(74) | 评论 (0) | 编辑收藏

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