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一:
用myeclipse中的傻瓜式添加spring组件。
修改web.xml文件内容,如下:(红色标记处)

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
 http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
 <context-param>
  <param-name>contextConfigLocation</param-name>
  <param-value>/WEB-INF/applicationContext-dwr.xml</param-value>
 </context-param>
 <listener>
  <listener-class>
   org.springframework.web.context.ContextLoaderListener
  </listener-class>
 </listener>
 <servlet>
  <servlet-name>dwr-invoker</servlet-name>
  <servlet-class>uk.ltd.getahead.dwr.DWRServlet</servlet-class>
  <init-param>
   <param-name>debug</param-name>
   <param-value>true</param-value>
  </init-param>
 </servlet>

 <servlet-mapping>
  <servlet-name>dwr-invoker</servlet-name>
  <url-pattern>/dwr/*</url-pattern>
 </servlet-mapping>
 <welcome-file-list>
  <welcome-file>index.jsp</welcome-file>
 </welcome-file-list>
</web-app>
二:
将文件交给spring来管理

<!DOCTYPE dwr PUBLIC "-//GetAhead Limited//DTD Direct Web Remoting 2.0//EN" "http://getahead.org/dwr//dwr20.dtd">

<dwr>
  <allow>
    <create creator="spring" javascript="DWRUserAccess">
      <param name="beanName" value="dwrUserAccess"/>
    </create>
    <convert match="com.dwr.User" converter="bean"></convert>
  </allow>
</dwr>

三:
在web-inf下新建applicationContext-dwr.xml文件,内容如下
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">
<beans default-autowire="byName">  
    <bean name="dwrUserAccess" class="com.dwr.DWRUserAccess"></bean>
</beans>


OK。
posted on 2008-08-13 11:22 飞飞 阅读(1568) 评论(0)  编辑  收藏

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