﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>BlogJava-helloworld 路慢慢其修远兮，吾上下而求索-随笔分类-数学定理</title><link>http://www.blogjava.net/zhaochengming/category/28439.html</link><description /><language>zh-cn</language><lastBuildDate>Fri, 28 Dec 2007 07:12:28 GMT</lastBuildDate><pubDate>Fri, 28 Dec 2007 07:12:28 GMT</pubDate><ttl>60</ttl><item><title>最大公约数(Euclid算法)</title><link>http://www.blogjava.net/zhaochengming/archive/2007/12/28/171148.html</link><dc:creator>helloworld2008</dc:creator><author>helloworld2008</author><pubDate>Fri, 28 Dec 2007 04:48:00 GMT</pubDate><guid>http://www.blogjava.net/zhaochengming/archive/2007/12/28/171148.html</guid><wfw:comment>http://www.blogjava.net/zhaochengming/comments/171148.html</wfw:comment><comments>http://www.blogjava.net/zhaochengming/archive/2007/12/28/171148.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.blogjava.net/zhaochengming/comments/commentRss/171148.html</wfw:commentRss><trackback:ping>http://www.blogjava.net/zhaochengming/services/trackbacks/171148.html</trackback:ping><description><![CDATA[<p>gcd(a,b) = gcd(b, a mod b)<br />
<br />
求a,b的最大公约数d<br />
有 a = bk + r<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; a = x*d<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; b = y*d<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; -&gt;<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; r = a - bk (即a mod b)<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; r = xd - ydk<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; r = (x-yk)d<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 即d也可以被a mod b整除,d是a mod b的公约数<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 因为d是b的公约数<br />
所以 gcd(b,a mod b)成立</p>
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