BlogJava-Java Home-随笔分类-JAVA代码研读http://www.blogjava.net/yemoo/category/12202.htmlJava技术修炼中...zh-cnFri, 02 Mar 2007 01:56:06 GMTFri, 02 Mar 2007 01:56:06 GMT60根据用户输入判断百分制成绩对应等级http://www.blogjava.net/yemoo/archive/2006/07/10/57414.htmlYemoo'S Java BlogYemoo'S Java BlogSun, 09 Jul 2006 17:22:00 GMThttp://www.blogjava.net/yemoo/archive/2006/07/10/57414.htmlhttp://www.blogjava.net/yemoo/comments/57414.htmlhttp://www.blogjava.net/yemoo/archive/2006/07/10/57414.html#Feedback0http://www.blogjava.net/yemoo/comments/commentRss/57414.htmlhttp://www.blogjava.net/yemoo/services/trackbacks/57414.html import  java.io. * ;

 public   class  GradeLevel{
     public   static   void  main(String args[])  throws  IOException{
        BufferedReader keyin = new  BufferedReader( new  InputStreamReader(System.in));
        String x;
         int  y,n;
        System.out.println( " 请输入一个成绩: " );
        x = keyin.readLine();     // 读取一个字符串
        y = Integer.parseInt(x);     // 将输入的字符串x转换成整型数据y
        n = ( 99 - y) / 10 + 1 ;
        
         switch (n){
             case   1 :System.out.println( " A " ); break ;
             case   2 :System.out.println( " B " ); break ;
             case   3 :System.out.println( " C " ); break ;
             case   4 :System.out.println( " D " ); break ;
             default :System.out.println( " 不及格 " );
        }
    }
}
要注意以下两个问题:
1,建立输入流的类名:BufferedReader而不是BufferReader,不要少写了ed.然后在BufferedReadereizhong建立InputStreamReader类.最后可以调用system.in的realLine方法读入一行数据.
2,将百分制转换成与1.2.3.4与其他等5种情况的简单公式:(99-y)/10+1;

Yemoo'S Java Blog 2006-07-10 01:22 发表评论
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