﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>BlogJava-lqxue-随笔分类-other</title><link>http://www.blogjava.net/lqxue/category/26912.html</link><description /><language>zh-cn</language><lastBuildDate>Sun, 11 Nov 2007 08:31:25 GMT</lastBuildDate><pubDate>Sun, 11 Nov 2007 08:31:25 GMT</pubDate><ttl>60</ttl><item><title>二叉树的遍历</title><link>http://www.blogjava.net/lqxue/archive/2007/11/09/159389.html</link><dc:creator>lqx</dc:creator><author>lqx</author><pubDate>Fri, 09 Nov 2007 08:11:00 GMT</pubDate><guid>http://www.blogjava.net/lqxue/archive/2007/11/09/159389.html</guid><wfw:comment>http://www.blogjava.net/lqxue/comments/159389.html</wfw:comment><comments>http://www.blogjava.net/lqxue/archive/2007/11/09/159389.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.blogjava.net/lqxue/comments/commentRss/159389.html</wfw:commentRss><trackback:ping>http://www.blogjava.net/lqxue/services/trackbacks/159389.html</trackback:ping><description><![CDATA[<span lang="EN-US" style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-bidi-font-size: 12.0pt; mso-fareast-font-family: 宋体; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><v:shapetype id="_x0000_t75" stroked="f" filled="f" path="m@4@5l@4@11@9@11@9@5xe" o:preferrelative="t" o:spt="75" coordsize="21600,21600">&nbsp;<v:stroke joinstyle="miter"></v:stroke><v:formulas><v:f eqn="if lineDrawn pixelLineWidth 0"></v:f><v:f eqn="sum @0 1 0"></v:f><v:f eqn="sum 0 0 @1"></v:f><v:f eqn="prod @2 1 2"></v:f><v:f eqn="prod @3 21600 pixelWidth"></v:f><v:f eqn="prod @3 21600 pixelHeight"></v:f><v:f eqn="sum @0 0 1"></v:f><v:f eqn="prod @6 1 2"></v:f><v:f eqn="prod @7 21600 pixelWidth"></v:f><v:f eqn="sum @8 21600 0"></v:f><v:f eqn="prod @7 21600 pixelHeight"></v:f><v:f eqn="sum @10 21600 0"></v:f></v:formulas><v:path o:connecttype="rect" gradientshapeok="t" o:extrusionok="f"></v:path><o:lock aspectratio="t" v:ext="edit"></o:lock></v:shapetype></span> <img height="222" alt="" src="http://www.blogjava.net/images/blogjava_net/lqxue/1.png" width="257" border="0" /><br />
<p>&nbsp;</p>
<p><strong>前序遍历二叉树算法的框架是<br />
</strong>若二叉树为空，则空操作；<br />
否则<br />
访问根结点 (V)；<br />
前序遍历左子树 (L)；<br />
前序遍历右子树 (R)。</p>
<p>遍历结果<br />
- + a * b - c d / e f<br />
<br />
</p>
<p><strong>中序遍历二叉树算法的框架是：<br />
</strong>若二叉树为空，则空操作；<br />
否则<br />
中序遍历左子树 (L)；<br />
访问根结点 (V)；<br />
中序遍历右子树 (R)。</p>
<p>遍历结果<br />
&nbsp; a + b * c - d - e / f<br />
</p>
<p><br />
<br />
<strong>后序遍历二叉树算法的框架是<br />
</strong>若二叉树为空，则空操作；<br />
否则<br />
后序遍历左子树 (L)；<br />
后序遍历右子树 (R)；<br />
访问根结点 (V)。</p>
<p>遍历结果<br />
a b c d - * + e f / -</p>
<br />
参考文档：http://51zk.csai.cn/sjjg/200608291542281644.htm<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; http://faculty.math.tsinghua.edu.cn/faculty/~jli/teaching/2006/Fall/ds/347,32,后序遍历 (Postorder Traversal)
 <img src ="http://www.blogjava.net/lqxue/aggbug/159389.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.blogjava.net/lqxue/" target="_blank">lqx</a> 2007-11-09 16:11 <a href="http://www.blogjava.net/lqxue/archive/2007/11/09/159389.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>