BlogJava-On The Way-随笔分类-jsp/servlet

BlogJava-On The Way-随笔分类-jsp/servlethttp://www.blogjava.net/liangj/category/30378.htmlzh-cnWed, 26 Mar 2008 03:05:59 GMTWed, 26 Mar 2008 03:05:59 GMT60解决当FORM的ENCTYPE="multipart/form-data" 时request.getParameter()获取不到值的方法http://www.blogjava.net/liangj/archive/2008/03/26/188666.html梁健梁健Wed, 26 Mar 2008 02:38:00 GMThttp://www.blogjava.net/liangj/archive/2008/03/26/188666.htmlhttp://www.blogjava.net/liangj/comments/188666.htmlhttp://www.blogjava.net/liangj/archive/2008/03/26/188666.html#Feedback0http://www.blogjava.net/liangj/comments/commentRss/188666.htmlhttp://www.blogjava.net/liangj/services/trackbacks/188666.htmlSituation(原因):
javax.servlet.HttpServletRequest.getParameter(String) returns null when the ContentType is multipart/form-data

Solutions(解决办法):

Solution A:

1. download http://www.servlets.com/cos/index.html
2. invoke getParameters() on com.oreilly.servlet.MultipartRequest

Solution B:

    1. download http://jakarta.apache.org/commons/fileupload/
    2. invoke readHeaders() in org.apache.commons.fileupload.MultipartStream
    Or
    1. Invoke parseRequest(request) on org.apache.commons.fileupload.FileUploadBase which returns list of org.apache.commons.fileupload.FileItem objects.
   2. Invoke isFormField() on each of the FileItem objects. This determines whether the file item is a form paramater or stream of uploaded file.
   3. Invoke getFieldName() to get parameter name and getString() to get parameter value on FileItem if it's a form parameter. Invoke write(java.io.File) on FileItem to save the uploaded file stream to a file if the FileItem is not a form parameter.

Solution C:

1. download http://users.boone.net/wbrameld/multipartformdata/
2. invoke getParameter on com.bigfoot.bugar.servlet.http.MultipartFormData

Solution D:

Use Struts. Struts 1.1 handles this automatically.

梁健 2008-03-26 10:38 发表评论

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