BlogJava-道非道 非常道-文章分类-算法http://www.blogjava.net/gen-sky/category/42789.html终日昏昏醉梦间，忽闻春尽强登山， 因过竹院逢僧话，偷得浮生半日闲。zh-cnThu, 19 Nov 2009 07:14:49 GMTThu, 19 Nov 2009 07:14:49 GMT60求一算法http://www.blogjava.net/gen-sky/articles/302913.html星期五星期五Thu, 19 Nov 2009 06:13:00 GMThttp://www.blogjava.net/gen-sky/articles/302913.htmlhttp://www.blogjava.net/gen-sky/comments/302913.htmlhttp://www.blogjava.net/gen-sky/articles/302913.html#Feedback0http://www.blogjava.net/gen-sky/comments/commentRss/302913.htmlhttp://www.blogjava.net/gen-sky/services/trackbacks/302913.html x%2=1;  x%3=2;   x%5=4;  x%6=5; x%7=0;

答案一：
        long x = 0;
        long i = 0l;
        boolean j = false;
        do{
            if(j){
                // x%5 == 4    表示对十取余时，只能是 4 或者 9 并且， x%2 == 1那么只能是 9
                if(i%10 == 9){
                    if(i%3 == 2 && i%6 == 5){
                        x = i;
                        break;
                    }
                }
            }
            // x%7 == 0  表示 x 值是 7 的倍数，所以每次增加 7 会减少循环
            i += 7;
            // x%2 == 1 表示  x 值不应该是偶数，那么，每次增加 7 时必顺间隔增加
            j = !j;
        }while(i < Long.MAX_VALUE);
        System.out.println(x);




星期五 2009-11-19 14:13 发表评论
]]>