﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>语源科技BlogJava-datalook</title><link>http://www.blogjava.net/datalook/</link><description /><language>zh-cn</language><lastBuildDate>Sat, 02 May 2026 09:26:05 GMT</lastBuildDate><pubDate>Sat, 02 May 2026 09:26:05 GMT</pubDate><ttl>60</ttl><item><title>数组补缺</title><link>http://www.blogjava.net/datalook/archive/2008/12/05/244629.html</link><dc:creator>datalook</dc:creator><author>datalook</author><pubDate>Fri, 05 Dec 2008 08:42:00 GMT</pubDate><guid>http://www.blogjava.net/datalook/archive/2008/12/05/244629.html</guid><wfw:comment>http://www.blogjava.net/datalook/comments/244629.html</wfw:comment><comments>http://www.blogjava.net/datalook/archive/2008/12/05/244629.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.blogjava.net/datalook/comments/commentRss/244629.html</wfw:commentRss><trackback:ping>http://www.blogjava.net/datalook/services/trackbacks/244629.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 今天开发的时候遇到个小问题，解决后拿出来晒晒，看看大家还有没有更好的办法，呵呵！<br><br>要求：两个字符串数组集合，A数组两个元素code和name，B数组两个元素code和number，需要把B数组中没有A数组的code进行补缺并number置零，并且要按A数组code的排序方式。<br><br>&nbsp;&nbsp;<a href='http://www.blogjava.net/datalook/archive/2008/12/05/244629.html'>阅读全文</a><img src ="http://www.blogjava.net/datalook/aggbug/244629.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.blogjava.net/datalook/" target="_blank">datalook</a> 2008-12-05 16:42 <a href="http://www.blogjava.net/datalook/archive/2008/12/05/244629.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>