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Python编程谜题-5

罗明 — Thu, 22 May 2008 09:45:00 GMT

应用python的pickle模块从序列化文件中构造对象，根据对象的构造解开谜题

详细描述 :

http://www.pythonchallenge.com/pc/def/peak.html

(peak hell连读发音类似pickle，谜题就是pickle模块的应用了)

解决方案代码:

import pprint,pickle,sys

pfile = open('banner.p')
data = pickle.load(pfile)
for row in data:
  for item in row:
    for index in range(item[1]):
      sys.stdout.write(item[0])
  print ''
pfile.close()

输出的对象构造：

罗明 2008-05-22 17:45 发表评论

编程谜题-4

罗明 — Fri, 09 May 2008 06:32:00 GMT

Follow the URL chain to get the result (the chain may contain over 300 URLs......)

谜题详细描述：http://www.pythonchallenge.com/pc/def/linkedlist.php

Python解决方案：

import urllib

nothing = "12345"
ii = 1
while ii<401:
  source = urllib.urlopen("http://www.pythonchallenge.com"
    + "/pc/def/linkedlist.php?nothing="+nothing).read()
  nothing=filter(str.isdigit, source)

  print nothing
  if source != "and the next nothing is " + nothing:
    print "source is not: and the next nothing is " + nothing
    print "source is: " + source
    nothing = raw_input("select which number?")
    print "you set " + nothing + " as nothing"
  ii+=1

罗明 2008-05-09 14:32 发表评论

编程谜题-3

罗明 — Thu, 08 May 2008 04:50:00 GMT

从一大堆字母里找出两边都刚好有3个大写字母的小写字母
详细描述：http://www.pythonchallenge.com/pc/def/equality.html

解决方案：

Python：
>>> import re
>>> re.findall(r'[a-z][A-Z][A-Z][A-Z][a-z][A-Z][A-Z][A-Z][a-z]', text)

罗明 2008-05-08 12:50 发表评论

编程谜题 - 2

罗明 — Wed, 07 May 2008 08:11:00 GMT

谜题描述：http://www.pythonchallenge.com/pc/def/ocr.html
从一大堆乱码中找出可以理解的信息（字母）

Java解决方案：

public class Test {

    public static void main(String[] args) throws Exception {
        URL url = new URL("http://www.pythonchallenge.com"
           + "/pc/def/ocr.html");
        BufferedReader reader = new BufferedReader(new
           InputStreamReader(url.openStream()));
        StringBuffer sb = new StringBuffer();
        int i = reader.read();
        while(i != -1)
        {
            if((i >= (int)'A' && i <= (int)'Z')
               || (i >= (int)'a' && i <= (int)'z'))
            {
                sb.append((char)i);
            }
            i = reader.read();
        }
        reader.close();
        String source = sb.toString();

//页面源码中最后一个单词是below
        System.out.println(
           source.substring(source.indexOf("below") + 5)
        );
    }
}

附Python和Shell：

Python:

>>> text = """

"""
>>> import string
>>> for i in text:
        if i in string.ascii_letters:
        print i,

Shell:
$ curl http://www.pythonchallenge.com/pc/def/ocr.html | grep -o [a-z]

罗明 2008-05-07 16:11 发表评论